-2x^2+3x+20=3x+12

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Solution for -2x^2+3x+20=3x+12 equation: 


Simplifying
-2x2 + 3x + 20 = 3x + 12

Reorder the terms:
20 + 3x + -2x2 = 3x + 12

Reorder the terms:
20 + 3x + -2x2 = 12 + 3x

Add '-3x' to each side of the equation.
20 + 3x + -3x + -2x2 = 12 + 3x + -3x

Combine like terms: 3x + -3x = 0
20 + 0 + -2x2 = 12 + 3x + -3x
20 + -2x2 = 12 + 3x + -3x

Combine like terms: 3x + -3x = 0
20 + -2x2 = 12 + 0
20 + -2x2 = 12

Solving
20 + -2x2 = 12

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-20' to each side of the equation.
20 + -20 + -2x2 = 12 + -20

Combine like terms: 20 + -20 = 0
0 + -2x2 = 12 + -20
-2x2 = 12 + -20

Combine like terms: 12 + -20 = -8
-2x2 = -8

Divide each side by '-2'.
x2 = 4

Simplifying
x2 = 4

Take the square root of each side:
x = {-2, 2}

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